Kody Brown is a reality television personality who appears on the TLC series “Sister Wives.” He is in a polygamous marriage with four wives: Meri, Janelle, Christine, and Robyn. While Kody has a total of 18 children, the number of children he has with each of his wives varies.
Janelle is Kody’s second wife, and they were married in 1993. Together, they have a total of six children: Logan, Madison, Hunter, Garrison, Gabriel, and Savanah.
Logan was born in 1994 and is Janelle and Kody’s oldest child. He graduated from college and now works in the health industry. Madison, born in 1995, is their second child and has since gotten married and has two children of her own. Hunter, born in 1997, is their third child and has since graduated from college and works in the tech industry. Garrison, born in 1999, is their fourth child and is currently attending college. Gabriel, born in 2001, is their fifth child and is still in high school. Savanah, born in 2004, is their youngest child and is currently in middle school.
Janelle has been an important part of the Brown family for many years and has played a major role in helping to raise all of Kody’s children. While their family structure may be unconventional, Janelle has said that she believes in the principles of polygamy and that it has allowed her to form deep relationships with all of her sister wives and their children.
In conclusion, Kody Brown and Janelle have six children together: Logan, Madison, Hunter, Garrison, Gabriel, and Savanah. While their family structure may be different from traditional families, they have shown that it is possible to create a strong and loving family dynamic with multiple partners and children.
